Singular Value Decomposition (SVD) and Principal Component Analysis (PCA)

نویسنده

  • Edo Liberty
چکیده

l=1 σlulv T l (1) ∀ l σl ∈ R, σl ≥ 0 (2) ∀ l, l 〈ul, ul′〉 = 〈vl, vl′〉 = δ(l, l) (3) To prove this consider the matrix AA ∈ R. Set ul to be the l’th eigenvector of AA . By definition we have that AAul = λlul. Since AA T is positive semidefinite we have λl ≥ 0. Since AA is symmetric we have that ∀ l, l 〈ul, ul′〉 = δ(l, l). Set σl = √ λl and vl = 1 σl Aul. Now we can compute the following: 〈vl, vl′〉 = 1 σ2 l ul AA ul = 1 σ2 l λl〈ul, ul′〉 = δ(l, l) We are only left to show that A = ∑m l=1 σlulv T l . To do that we examine the norm or the difference multiplied by a test vector w = ∑m i=1 αiui. ||w (A− m ∑

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تاریخ انتشار 2011